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Mechanics Projectiles T_T

an Athlete throws a heavy ball, ball is released at speed 10.3ms-1 at an angle of 35 degrees above the horizontal,the point of release is 1.68m above the ground.

a)Neglecting air resistance show that the equation of the path of the ball is aproximately y=0.7x-0.07x^2, where y is height in metres above the release point when it has travelled a horizontal distance of x metres...........

I have tried but cannot do this, can someone explain how to do this to me please
Original post by joyoustele
an Athlete throws a heavy ball, ball is released at speed 10.3ms-1 at an angle of 35 degrees above the horizontal,the point of release is 1.68m above the ground.

a)Neglecting air resistance show that the equation of the path of the ball is aproximately y=0.7x-0.07x^2, where y is height in metres above the release point when it has travelled a horizontal distance of x metres...........

I have tried but cannot do this, can someone explain how to do this to me please


Express t in terms of x. Sub t into y to get y-x relation.
Reply 2
Original post by RDKGames
Express t in terms of x. Sub t into y to get y-x relation.


Thank you RDK :smile: :smile: :smile:

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