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    an Athlete throws a heavy ball, ball is released at speed 10.3ms-1 at an angle of 35 degrees above the horizontal,the point of release is 1.68m above the ground.

    a)Neglecting air resistance show that the equation of the path of the ball is aproximately y=0.7x-0.07x^2, where y is height in metres above the release point when it has travelled a horizontal distance of x metres...........

    I have tried but cannot do this, can someone explain how to do this to me please
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    (Original post by joyoustele)
    an Athlete throws a heavy ball, ball is released at speed 10.3ms-1 at an angle of 35 degrees above the horizontal,the point of release is 1.68m above the ground.

    a)Neglecting air resistance show that the equation of the path of the ball is aproximately y=0.7x-0.07x^2, where y is height in metres above the release point when it has travelled a horizontal distance of x metres...........

    I have tried but cannot do this, can someone explain how to do this to me please
    Express t in terms of x. Sub t into y to get y-x relation.
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    (Original post by RDKGames)
    Express t in terms of x. Sub t into y to get y-x relation.
    Thank you RDK
 
 
 
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