Turn on thread page Beta
    • Thread Starter
    Offline

    16
    ReputationRep:
    I've managed to understand how to derive all the other equations, however, I'm struggling with the equation without acceleration, s = ½ (u+v).

    My textbook says to treat the area under the graph as the area of a trapezium, but I'm struggling to see it as a trapezium.
    Offline

    16
    ReputationRep:
    Have you tried drawing your own velocity-time graph? What do you come up with if you draw a v-t graph with the following: a particle starting with velocity u at a time t=0, that is accelerating with constant acceleration to a velocity v at a time t=t?
 
 
 
The home of Results and Clearing

1,495

people online now

1,567,000

students helped last year

University open days

  1. Sheffield Hallam University
    City Campus Undergraduate
    Tue, 21 Aug '18
  2. Bournemouth University
    Clearing Open Day Undergraduate
    Wed, 22 Aug '18
  3. University of Buckingham
    Postgraduate Open Evening Postgraduate
    Thu, 23 Aug '18
Poll
A-level students - how do you feel about your results?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.