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# Current-Voltage graph (I-V), what is Ohm's law in straight line form? watch

1. V=IR
1/R = I/V

So gradient of I-V graph is 1/R I think

How would I write Ohm's law for a I-V graph in terms of y=mx+c? Thanks

I think it's I = (1/R)(V) + c
c is the intercept (0 in this case)
3. Well ohm's law is the current and potential difference are directly proportional...So the IV graph needs to be directly proportional. Think about what that means in terms of the shape of the line

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Updated: October 24, 2017
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