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    The link to the paper is https://www.undergraduate.study.cam....paper_2016.pdf
    The answer is *spoiler alert* E, and I do not know how to derive the second probability in this answer. If someone could explain how to do this, that would be great, thank you.
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    (Original post by ilyacarey)
    The link to the paper is https://www.undergraduate.study.cam....paper_2016.pdf
    The answer is *spoiler alert* E, and I do not know how to derive the second probability in this answer. If someone could explain how to do this, that would be great, thank you.
    This is probably late but when after mutation 1 you end up with a chain of 7 nucleotides. Any of those can be deleted to leave behind 6 nucleotide which would code for 2 amino acids. It's only when Adenine is deleted that you end up with the triplet code for 2 arginines. From there it's 1/7*1/4.
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    (Original post by Kvothe the Arcane)
    This is probably late but when after mutation 1 you end up with a chain of 7 nucleotides. Any of those can be deleted to leave behind 6 nucleotide which would code for 2 amino acids. It's only when Alanine is deleted that you end up with the triplet code for 2 arginines. From there it's 1/7*1/4.
    Ah I get it now, thanks. I assume you meant adenine and not alanine?
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    (Original post by ilyacarey)
    Ah I get it now, thanks. I assume you meant adenine and not alanine?
    Yes sorry, brain fart.
 
 
 
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