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    A rhombus ABCD has vertices with position vectors a = pi + 5j, b = 2i + 12j, c = (q + 4)i + qj and d = 22i + 2j. Find the values of p and q. I really appreciate any help that can be given, I have tried countless number of times - if its possible could you give an explanation?
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    (Original post by tom sampson7)
    A rhombus ABCD has vertices with position vectors a = pi + 5j, b = 2i + 12j, c = (q + 4)i + qj and d = 22i + 2j. Find the values of p and q. I really appreciate any help that can be give, I have tried countless number of times - if its possible could you give an explanation?
    What are the properties of a rhombus?
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    None were stated.
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    (Original post by tom sampson7)
    None were stated.
    They don't have to be - it's assumed knowledge.
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    Do you mean opposite sides are parallel, all sides are equal and opposite angles are equal?
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    (Original post by tom sampson7)
    Do you mean opposite sides are parallel, all sides are equal and opposite angles are equal?
    Yes. Draw a rhombus, label its vertices with your points, and use those properties to deduce the answers.
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    Ive done this several times and keep getting different answers, do I need to find the length or just find the two vectors that are parallel to each other?
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    (Original post by tom sampson7)
    Ive done this several times and keep getting different answers, do I need to find the length or just find the two vectors that are parallel to each other?
    I'd just use the fact that CD=BC in length to find q then use the symmetry to get p.
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    Ah got ya, thank you very much
 
 
 
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