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# maths help watch

1. To complete a task in 30days, a company needs 4people each working for 7 hours per day.
The company decides to have 5 people each working for 6 hours per day.
Assuming that each person works at the same rate, how many days will the task take to complete?
2. Have you got any ideas so far? Try thinking about how much work goes into completing the task in 30 days.
3. (Original post by jesusjessica15)
To complete a task in 30days, a company needs 4people each working for 7 hours per day.
The company decides to have 5 people each working for 6 hours per day.
Assuming that each person works at the same rate, how many days will the task take to complete?
x = 7*4 = 28 * 30 = 840
y = 5*6 = 30

x/y = 28 days

Unless I am missing something
4. (Original post by hatedigi)
Have you got any ideas so far? Try thinking about how much work goes into completing the task in 30 days.
no not really
5. If 4 workers spend 7 hours working each day we know they do 28 hours worth of work per day combined. If 28 hours worth of work must be done over 30 days that means 840 hours of work must be done in total to complete the project. If you have five people do the 840 hours worth of work, each would have to complete 168 hours. If they do 6 hours per day (168/6) they would need to spend 28 days working (making it the faster option). This is of course ignoring ideas such as fatigue and competence of said workers but I'm assuming you don't need to take this into consideration. Hope this has helped xoxo
6. (Original post by flatline)
x = 7*4 = 28 * 30 = 840
y = 5*6 = 30

x/y = 28 days

Unless I am missing something
thank you so much, it's probably right
7. (Original post by Elizzey)
If 4 workers spend 7 hours working each day we know they do 28 hours worth of work per day combined. If 28 hours worth of work must be done over 30 days that means 840 hours of work must be done in total to complete the project. If you have five people do the 840 hours worth of work, each would have to complete 168 hours. If they do 6 hours per day (168/6) they would need to spend 28 days working (making it the faster option). This is of course ignoring ideas such as fatigue and competence of said workers but I'm assuming you don't need to take this into consideration. Hope this has helped xoxo
thank you so much for your help
8. (Original post by jesusjessica15)
thank you so much, it's probably right
np b.
9. you can work out the man hours needed:

4 x 7 x 30

so when there are 5 workers there for 6 hours a day....

5 x 6 x ? = 4 x 7 x 30

then it is straightforward to find ?
10. Is mathsgenie a good revision tool to use for the new 9-1 GCSE mathematics? Has anyone used it and will it get me a 4
11. (Original post by Maro122)
Is mathsgenie a good revision tool to use for the new 9-1 GCSE mathematics? Has anyone used it and will it get me a 4
Hi mathsgenie is actually really good, i use it for self- maths revision. it has different grades for you to revise from, it gives you revision material, then some questions
and solutions for them...

i really recommend it!
12. (Original post by jesusjessica15)
Hi mathsgenie is actually really good, i use it for self- maths revision. it has different grades for you to revise from, it gives you revision material, then some questions
and solutions for them...
i really recommend it!
Hey thanks fir your reply, do you think it can help me achieve a grade 4 or above?
13. 28 hours(7*4) a day = k/30 days since hours worked a day is inversely proportional to days it takes. Therefore, k=28*30

now, since k is constant, 30hours(6*5 hours a day)* number of days=28*30

Therefore, days=28.

I hope that made sense as they kinda swap around if you know what I mean.
14. (Original post by Maro122)
Hey thanks fir your reply, do you think it can help me achieve a grade 4 or above?
sorry, i couldn't reply sooner, yes of course you can achieve above 4, it has different topics in different grades.

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