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    i need help on the last 2 part

    31. Dilution Effects for Moles Calculations•a )•i) n(NaOH) in 250cm3=4/40 = 0.1•ii) n(NaOH) in 25cm3= 0.1/10 = 0.01•iii) c(NaOH) in titration = 0.01x1000/25 = 0.4
    •b)Lithium can be used to make Lithium Hydroxide••Li + 2H2O LiOH + H2•Lithium Hydroxide can be neutralised by Sulfuric Acid •2LiOH + H2SO4Li2SO4+ H2O••A student dissolved Lithium in water and made up the solution to 100cm3in a volumetric flask. •The student forgot to make a note of the mass of lithium used. •The student then decided to do a titration to work out how much lithium they used. ••10cm3of LiOH needed 12.5cm3of H2SO4(0.0200moldm-3) for complete neutralisation. ••i)Calculate the amount, in moles of LiOH that reacted?•ii)Calculate the amount, in moles of LiOH that was present originally in the volumetric flask.
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