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Maths - logs explanation

hi, was wondering if someone could explain how this website has gone from (log4(x+1))/2 to log4((x+1)^1/2)

my teacher wasnt here for the lesson so i had to self teach. i understanfd the actual change of base formula, i just dont understand the bit above, feel like im missing something really obvious haha

thanks

link, example number 4, first bullet point: http://www.analyzemath.com/logarithmic_equations/solve.html
Reply 1
Original post by thenbhd
hi, was wondering if someone could explain how this website has gone from (log4(x+1))/2 to log4((x+1)^1/2)

my teacher wasnt here for the lesson so i had to self teach. i understanfd the actual change of base formula, i just dont understand the bit above, feel like im missing something really obvious haha

thanks

link, example number 4, first bullet point: http://www.analyzemath.com/logarithmic_equations/solve.html


hi this is a simple case of xloga = loga to power of X rule. the log4(x+1)/2 is the same as 1/2Xlog4(x+1) which = log4(x+1) to power of half
Original post by thenbhd
hi, was wondering if someone could explain how this website has gone from (log4(x+1))/2 to log4((x+1)^1/2)


log[4(x+1)]212log[4(x+1)]\frac{log[4(x+1)]}{2} \equiv \frac{1}{2} \cdot log[4(x+1)]

Since alog(b)log(b)aa \cdot log(b) \equiv log(b)^{a}

Can you work from here?
Reply 3
Original post by Okdmd46
hi this is a simple case of xloga = loga to power of X rule. the log4(x+1)/2 is the same as 1/2Xlog4(x+1) which = log4(x+1) to power of half


omg! thank you! feel so silly i couldn't spot that haha
Reply 4
Original post by ManLike007
log[4(x+1)]212log[4(x+1)]\frac{log[4(x+1)]}{2} \equiv \frac{1}{2} \cdot log[4(x+1)]

Since alog(b)log(b)aa \cdot log(b) \equiv log(b)^{a}

Can you work from here?


thank you !

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