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    Complete combustion of 1.80g of compound L produced 2.64g of CO2, 1.08g of water and 1.92g of sulphur dioxide
    calculate the empirical formula of L????
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    (Original post by saarahtalha)
    Complete combustion of 1.80g of compound L produced 2.64g of CO2, 1.08g of water and 1.92g of sulphur dioxide
    calculate the empirical formula of L????
    You can deduce this compound contains carbon, hydrogen and sulfur.

    Calculate the number of moles of CO2, H2O and SO2 produced. Divide by the smallest number of moles to find their ratios as whole numbers.
    Relate these ratios back to the compound L. You need to consider that 2 hydrogen atoms in L are required for each water molecule, and that 1 carbon for each CO2 and 1 sulfur for each SO2.
 
 
 
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