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Bayes Theorem help watch

1. (Original post by SWISH99)
So, what have you done and where are you stuck?
2. (Original post by ghostwalker)
So, what have you done and where are you stuck?
not sure how to explain it
3. (Original post by SWISH99)
not sure how to explain it
P(A|B) < P(A)

Means, the probabilty of A happening is reduced if B has occurred.

And from this you've deduced, the probability of B happening is reduced if A has occurred.

So, the presence of either event adversely effects the probability of the other occuring.
4. (Original post by ghostwalker)
P(A|B) < P(A)

Means, the probabilty of A happening is reduced if B has occurred.

And from this you've deduced, the probability of B happening is reduced if A has occurred.

So, the presence of either event adversely effects the probability of the other occuring.
Ok I understand this part. But how do you show that the probability of B happening is reduced if A has occurred
5. (Original post by SWISH99)
Ok I understand this part. But how do you show that the probability of B happening is reduced if A has occurred
I thougth from your first post, that you'd done that part.
Start with Bayes' theorem, and rearrange it to get P(A|B)/P(A) on one side. What do you know about the value of this, and hence the value of the other side, and hence...

See what you can do.

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