A 25.0 mL sample of sodium sulfate solution was analyzed by adding an excess of barium chloride solution to produce barium sulfate crystals which were filtered from the solution.
Na2SO4(aq)+ BaCl2(aq) ---->2NaCl (aq)+BaSO4 (s)
If 5.719 g of barium sulfate were obtained what was the molarity of the original Na2SO4 solution?
A metal M was converted to the chloride MCl2. Then a solution of the chloride was treated with silver nitrate to give silver chloride crystals which were filtered from the solution.
MCl2(aq)+2 AgNO3(aq) ---> M(NO3)2 (aq)+2 AgCl(s)
If 2.434g of the metal gave 7.964 g of silver chloride what is the atomic weight of the metal? What is the mental?
Thanks to those who answer. ;-; Can someone show steps so I can find out what I did incorrectly.
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- Thread Starter
- 01-11-2017 12:48
- 01-11-2017 12:59
I don't know what the mental is.
What have you tried so far? That way, we can tell you what you did incorrectly.