Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    • Thread Starter

    When titrated with 25cm^3 of 0.05 M NaOH, it took 11.975 cm^3 of an unknown diprotic acid for a full neutralisation.

    The acid solution was made by dissolving 1.5g of solid acid in 250cm^3 of distilled water.

    The balanced equation for this reaction is 2NaOH + H2X -> Na2X + H2O.

    How can I work out the molar mass of the diprotic acid from this information? I know it is between 110 and 130
    Posted on the TSR App. Download from Apple or Google Play

    It is a fairly simple molar calc. using c =nv and n = m/Mr.

    Where are you struggling?
Submit reply
Turn on thread page Beta
Updated: November 1, 2017
Do you like carrot cake?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.