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Differentiation of Exponential Functions - Question watch

1. How do I go about differentiating xex^2 ?

I started by letting u = x and v = ex^2 , so du/dx = 1 but I don't know how to find dv/dx.

Any help would be greatly appreciated!

Thanks!
2. (Original post by grace15)
How do I go about differentiating xex^2 ?

I started by letting u = x and v = ex^2 , so du/dx = 1 but I don't know how to find dv/dx.

Any help would be greatly appreciated!

Thanks!
Use the chain rule on

Let
3. (Original post by ghostwalker)
Use the chain rule on
So if I let y= (ex )2 then dy/dx = 2 (ex )(ex ) = 2ex^2 ?
4. So, you have to do x' * (e^(x^2)) + x*((e^(x^2))'
Its the formula u'v + uv'
5. (Original post by grace15)
So if I let y= (ex )2 then dy/dx = 2 (ex )(ex ) = 2ex^2 ?
I edited my previous post to suggest the substitution.

NOTE:

Edit:

6. So if I let v=ew and let w = x2 then dy/dx of ex^2 is 2xex^2 ?

Then would I use the product rule to get dy/dx = x(2xex^2 ) + ex^2 ?

Which would simplify to ex^2 (2x2 + 1) ?

Is this correct?
7. Yes.
8. (Original post by grace15)
So if I let v=ew and let w = x2 then dy/dx of ex^2 is 2xex^2 ?
Yes.

Then would I use the product rule to get dy/dx = x(2xex^2 ) + ex^2 ?

Which would simplify to ex^2 (2x2 + 1) ?

Is this correct?
And yes.
9. (Original post by ghostwalker)
Yes.

And yes.
Great! Thank you very much for your help!

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