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    Hi, can someone help me with this question
    A student heats 3.25 g of a hydrated Group 1 carbonate in a crucible, until all the water has evaporated;
    M2CO3•10H2O → M2CO3 + 10H20
    After heating, 1.20 g of the anhydrous Group 1 carbonate forms.
    Calculate the relative formula mass of the anhydrous Group 1 carbonate and hence, identify the Group 1 metal M
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    1. Find number of moles of hydrated Metal Carbonate using n=mass/mr and sub in X for mr of the metal. E.g 3.25/(240 2X)=n
    2. Since ratio of moles is 1:1, equate to find mr of anhydrous metal carbonate in the 1.2 grams. n=mass/mr so mr=mass/n 60 2X=(1.2)/(3.25/(240 2X))
    3. Solve to find X.
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    (Original post by AvogadrosAvocado)
    1. Find number of moles of hydrated Metal Carbonate using n=mass/mr and sub in X for mr of the metal.
    2. Since ratio of moles is 1:1, equate to find mr of anhydrous metal carbonate in the 1.2 grams.
    3. Solve to find X.
    4. Use value of X to identify metal.
    Posted on the TSR App. Download from Apple or Google Play
 
 
 
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