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    Hi can someone explain to me how to do this question?

    The speed of motion of a trolley before and after (1.7 ± 0.1)s of acceleration is measured. Before the acceleration, the trolley moved (100 ± 1)mm in (1.78 ± 0.01)s(; after the acceleration it moved the same distance in (0.74 ± 0.01)s. Calculate the relative uncertainty of the measured acceleration. (Equation: Acceleration=change in velocity/time taken to accelerate)

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    (Original post by Hollster_Hol)
    Hi can someone explain to me how to do this question?

    The speed of motion of a trolley before and after (1.7 ± 0.1)s of acceleration is measured. Before the acceleration, the trolley moved (100 ± 1)mm in (1.78 ± 0.01)s(; after the acceleration it moved the same distance in (0.74 ± 0.01)s. Calculate the relative uncertainty of the measured acceleration. (Equation: Acceleration=change in velocity/time taken to accelerate)

    Thanks
    If I do this right, you have to consider the differences in your calculation. If you do, you have to consider the minimum and maximum value. The difference of speed of motion is 0.2 (1,76 the minimum, 1,78 the maximum). Analogous you calculate the other differences. For the distance of the trolley, it is 2, the time in which the trolley arrive this distance is 0,02 (after and before the acceleration).

    calculate the change of velocity first. It is d(v) = d(s)/d(t); d(s) = 2 mm and d(t) = 0,02 s

    After that you should be able to calculate the acceleration according to the given formula.
 
 
 
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