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    30g of ice at 0.00 degrees Celcius is quickly added to a calorimeter at 24.20 degrees celcius. the final temperature comes to 2.60 degrees celcius. What is the heat capacity of the calorimeter. GIven fusion of ice is 334J/g and capacity of ice is 2.06 J/gC and cpacity of water is 4.18J/gC

    can someone tell me how to do this please
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    When the calorimeter cools down energy is released, this energy is used to melt the ice and raise its temperature to 2.60 degrees.

    So equate energy lost by calorimeter to the energy gained by the ice and solve for the specific heat capacity of the calorimeter

    (Original post by lolatmylifeee)
    30g of ice at 0.00 degrees Celcius is quickly added to a calorimeter at 24.20 degrees celcius. the final temperature comes to 2.60 degrees celcius. What is the heat capacity of the calorimeter. GIven fusion of ice is 334J/g and capacity of ice is 2.06 J/gC and cpacity of water is 4.18J/gC

    can someone tell me how to do this please
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    Please dont post ur question twice!
    Posted on the TSR App. Download from Apple or Google Play
 
 
 
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