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C3 differentation with point of curve help !! watch

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    find the equation of the normal to the curve y=(x+4)/(x^2+1) at the point (0,4)
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    (Original post by yaaasminb)
    find the equation of the normal to the curve y=(x+4)/(x^2+1) at the point (0,4)
    Differentiate, find the gradient at the point, get the -ve reciprocal of the point, plug the point and the new gradient in your line construction method. Job done.
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    Differentiate the equation of y = (x+4)/(x^2+1) to get the gradient
    dy/dx = 1/2x
    Because you are finding the normal you will need to reciprocate to get 2x/1
    Then substitute in the x value of 0 into the differentiated value.
    m = 0
    Use y - y(1) = m(x - x(1))
    y - 4 = 0(x - 0)
    You should get y = 4
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    (Original post by NatKH)
    Differentiate the equation of y = (x+4)/(x^2+1) to get the gradient
    dy/dx = 1/2x
    Because you are finding the normal you will need to reciprocate to get 2x/1
    Then substitute in the x value of 0 into the differentiated value.
    m = 0
    Use y - y(1) = m(x - x(1))
    y - 4 = 0(x - 0)
    You should get y = 4
    1. You're incorrect,
    2. Please don't post full solutions.
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    (Original post by RDKGames)
    1. You're incorrect,
    2. Please don't post full solutions.
    Oh, sorry my bad
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    Have you learnt about the quotient, chain and product rules? Hint: One of those can be applied here Use it and see how far you get. Then post your working here and we can help you out more if needed.
 
 
 
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