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# Can anyone help on this A level Bio respiration question? watch

1. Hi, so this is a calculation question and I just can't get the right answer!

'The combined store of oxygen in a 450 kg Weddell seal is about 30 litres. The average rate of consumption in tissues is about 250cm^3 kg-1 hour -1'

Calculate the time you would expect a 450kg seal to be able to remain under water, respiring aerobically.'

(the answer is 16 minutes)

Thanks in advance!
2. first find the rate of oxygen conversion per hour for the seal: 450Kg x 250cm^3= 112500cm^3 per hour.Find the volume of oxygen stored in the seal (1l=1000cm^3)=30 x 1000= 30000 cm^3so we know our seal consumes 112500 cm^3 of oxygen per hour which is 1875 cm^3 per minute. Divide 30000 by 1875 to give you the minutes it takes for the seal to consume its oxygen supply=16 minutes
3. (Original post by tremen222)
first find the rate of oxygen conversion per hour for the seal: 450Kg x 250cm^3= 112500cm^3 per hour.Find the volume of oxygen stored in the seal (1l=1000cm^3)=30 x 1000= 30000 cm^3so we know our seal consumes 112500 cm^3 of oxygen per hour which is 1875 cm^3 per minute. Divide 30000 by 1875 to give you the minutes it takes for the seal to consume its oxygen supply=16 minutes
Thank you!
4. Okay so...

1 hour = 250cm3 (per 1kg)
1 hour therefore = 0.25 litres

Therefore if 0.25 = 1kg
450kg = 112.5 litres.

SO 112.5/60 = 1.875 litres oxygen used per min.

1.875 = 1 min
It has 30 litres of oxygen

SO 30/1.875 = 16 minutes!

Oops! Just realised someone had already done it!! Sorry!
5. (Original post by GCSEStudent903)
Okay so...

1 hour = 250cm3 (per 1kg)
1 hour therefore = 0.25 litres

Therefore if 0.25 = 1kg
450kg = 112.5 litres.

SO 112.5/60 = 1.875 litres oxygen used per min.

1.875 = 1 min
It has 30 litres of oxygen

SO 30/1.875 = 16 minutes!

Oops! Just realised someone had already done it!! Sorry!
Na I appreciate it thanks!

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