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# Hardy-Weinberg Equations watch

1. Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
Can anyone help?
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3. (Original post by millie.sykes)
Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
Can anyone help?
Perhaps there's a typo in the question - try using the Harvey Weinstein Allegations instead.
4. omg these were my fav to do in bio a level! sadly it's been two years since i've done them and can't remember how to do them! Theres some really good YouTube videos on them though
5. (Original post by millie.sykes)
Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
Can anyone help?
p^2=0.04
p=0.2
p+q=1
0.2+q=1
q=0.8

p^2+2pq+q^2=1
Blue feathered = 2pq
2x0.8x0.2=0.32
0.32x100=32%

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