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Hardy-Weinberg Equations watch

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    Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
    Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
    On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
    Can anyone help?
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.
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    (Original post by millie.sykes)
    Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
    Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
    On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
    Can anyone help?
    Perhaps there's a typo in the question - try using the Harvey Weinstein Allegations instead.
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    omg these were my fav to do in bio a level! sadly it's been two years since i've done them and can't remember how to do them! Theres some really good YouTube videos on them though
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    (Original post by millie.sykes)
    Hey, I have been given a question for homework and I don't know how to work it out using the equation... here is the question
    Feather colour in one species of chicken is controlled by a pair of dominant alleles which are not sex-linked. The allele CB codes for black feathers and the allele CW codes for white feathers. Heterozygous are blue feathered.
    On a farm 4% of chickens are black-feathered, use the Hardy-Weinberg equation to calculate the percentage of this population that you would expect to be blue feathered.
    Can anyone help?
    p^2=0.04
    p=0.2
    p+q=1
    0.2+q=1
    q=0.8

    p^2+2pq+q^2=1
    Blue feathered = 2pq
    2x0.8x0.2=0.32
    0.32x100=32%
 
 
 
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