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    Which would contain 9.03 × 1023 oxygen atoms?
    A 0.25 mol aluminium oxide
    B 0.75 mol sulfur dioxide
    C 1.5 mol sulfur trioxide
    D 3.0 mol water

    I would really appreciate it if someone showed me how to do the working. The answer scheme says it's B.
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    In 0.75 mol of SO2 you would have 0.75 x 2=1.5 mol of oxygen, time that by the avogadro constant to get number of oxygen atoms 1.5 x (6.02 x 10^23) =9.03 x 10^23
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    (Original post by Rachoo1)
    In 0.75 mol of SO2 you would have 0.75 x 2=1.5 mol of oxygen, time that by the avogadro constant to get number of oxygen atoms 1.5 x (6.02 x 10^23) =9.03 x 10^23
    Thank you very much
 
 
 
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