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# Calculate △fH for S02 watch

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1. 2H2S + SO2 -> 3S + 2H20

△H: -145.6 kJmol^-1

△fH:

H2S = -20.6
S02 = ?
S = 0
H20 = -241.8

This is what I did:

First I rearranged the equation to give me S02 = (2x-241.8) - (2x-20.6) + 145.6.
Simplified, this gave me -483.6 - 104.4 to give me -588.

The actual answer is -296.8 and I'm not sure how to get that so any help would be appreciated, thanks.
2. -145.6 = - (2 x -20.6) - x + (3 x 0) + (2 x -241.8)
x = -296.8

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Updated: November 7, 2017
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