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    For part C, Watching an examsolutions video. Here's the question
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    I'm watching ExamSolutions go through part C and he says that the minimum was when cos(theta-73.74)=1, which I get. Then, he says that theta-73.74=0 (since inverse cos of 1 is 0. However, why is it 0? How come it isn't 360 either? Using 360 would give you a different answer completely, but cos(360) is 1 too.

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    Can you explain it please?
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    (Original post by vector12)
    For part C, Watching an examsolutions video. Here's the question

    I'm watching ExamSolutions go through part C and he says that the minimum was when cos(theta-73.74)=1, which I get. Then, he says that theta-73.74=0 (since inverse cos of 1 is 0. However, why is it 0? How come it isn't 360 either? Using 360 would give you a different answer completely, but cos(360) is 1 too.

    Can you explain it please?
    Yeah but then \theta \not\in (0,150) as the question specifies.
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    (Original post by vector12)
    For part C, Watching an examsolutions video. Here's the question
    Name:  Screenshot_130.png
Views: 5
Size:  351.8 KB

    I'm watching ExamSolutions go through part C and he says that the minimum was when cos(theta-73.74)=1, which I get. Then, he says that theta-73.74=0 (since inverse cos of 1 is 0. However, why is it 0? How come it isn't 360 either? Using 360 would give you a different answer completely, but cos(360) is 1 too.

    Can you explain it please?
    can it be 360 with the restriction of theta given in the question?
 
 
 
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