Hey there! Sign in to join this conversationNew here? Join for free

M2 chapter 4 question please help Watch

Announcements
    • Thread Starter
    Offline

    12
    ReputationRep:
    from the textbook. I got the answer to( a) and I know how to get (b) with the long method involving suvat equations as well as "e" but how come the working out on the solution bank simply shows they found b by simply multiplying 0.7 by the answer to a? Name:  20171108_195314-1-compressed.jpg.jpeg
Views: 6
Size:  126.9 KB
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    12
    ReputationRep:
    Name:  20171108_195314-1-compressed.jpg.jpeg
Views: 4
Size:  126.9 KB
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    12
    ReputationRep:
    I tried to post a picture of the question idk why its refusing.
    Posted on the TSR App. Download from Apple or Google Play
    • Community Assistant
    • Welcome Squad
    Offline

    20
    ReputationRep:
    (Original post by sarah99630)
    ...
    Because it's like a projectile. It drops from the height, hits the ground with speed u_1=U, so it rebounds with speed v_1=eU, which means that will be the speed when it will hit the ground again, so u_2=eU, hence after the second bounce the coeff is applied again, so v_2 = e^2U = e v_1
    Offline

    15
    ReputationRep:
    (Original post by sarah99630)
    from the textbook. I got the answer to( a) and I know how to get (b) with the long method involving suvat equations as well as "e" but how come the working out on the solution bank simply shows they found b by simply multiplying 0.7 by the answer to a? Name:  20171108_195314-1-compressed.jpg.jpeg
Views: 6
Size:  126.9 KB
    Is this OCR?
    • Thread Starter
    Offline

    12
    ReputationRep:
    (Original post by joyoustele)
    Is this OCR?
    edexcel.
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    12
    ReputationRep:
    (Original post by RDKGames)
    Because it's like a projectile. It drops from the height, hits the ground with speed u_1=U, so it rebounds with speed v_1=eU, which means that will be the speed when it will hit the ground again, so u_2=eU, hence after the second bounce the coeff is applied again, so v_2 = e^2U = e v_1
    thank you so much for your help.
    Posted on the TSR App. Download from Apple or Google Play
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Will you be richer or poorer than your parents?
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.