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    from the textbook. I got the answer to( a) and I know how to get (b) with the long method involving suvat equations as well as "e" but how come the working out on the solution bank simply shows they found b by simply multiplying 0.7 by the answer to a? Name:  20171108_195314-1-compressed.jpg.jpeg
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    I tried to post a picture of the question idk why its refusing.
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    (Original post by sarah99630)
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    Because it's like a projectile. It drops from the height, hits the ground with speed u_1=U, so it rebounds with speed v_1=eU, which means that will be the speed when it will hit the ground again, so u_2=eU, hence after the second bounce the coeff is applied again, so v_2 = e^2U = e v_1
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    (Original post by sarah99630)
    from the textbook. I got the answer to( a) and I know how to get (b) with the long method involving suvat equations as well as "e" but how come the working out on the solution bank simply shows they found b by simply multiplying 0.7 by the answer to a? Name:  20171108_195314-1-compressed.jpg.jpeg
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Size:  126.9 KB
    Is this OCR?
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    (Original post by joyoustele)
    Is this OCR?
    edexcel.
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    (Original post by RDKGames)
    Because it's like a projectile. It drops from the height, hits the ground with speed u_1=U, so it rebounds with speed v_1=eU, which means that will be the speed when it will hit the ground again, so u_2=eU, hence after the second bounce the coeff is applied again, so v_2 = e^2U = e v_1
    thank you so much for your help.
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