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1. a, factorise the expression x^2 -10x+16
b. hence or otherwise solve the equation 8^2y -10(8^y) +16

i have managed to do a and i have the answer for b. i just don't know how to do the working out. Can anyone help me please.
2. x^2 = (x )(x )
2 numbers that add to make -10 and times to make 16
-8,-2
-8-2=-10
-8x-2=16
so therefore = (x-8)(x-2)

can u rephrase the second question is it (8^2)times Y-10 or (8^2Y)-10
3. (Original post by jamesgillian123)
x^2 = (x )(x )
2 numbers that add to make -10 and times to make 16
-8,-2
-8-2=-10
-8x-2=16
so therefore = (x-8)(x-2)

can u rephrase the second question is it (8^2)times Y-10 or (8^2Y)-10
it's 8 then the power 2y subtract 10(8 power of y) then +16
4. You're gotten x = 8, and x = 2 for the first equation.
You can write the next as 8^y = u, then just replace the 8^y with the u, you'll get again 8 and 2 for the factorisation.

Now 8^y = 8
y = 1
and 8^y = 2
y = 1/3

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