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    Cu(H2O)6^2+ (aq) + 2NH3 (aq) -> Cu(H2O)4(OH)2 (s) + 2NH4^+ (aq)

    Can someone please explain to me how I would go about turning this into an ionic equation? Thanks
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.
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    (Original post by Jessinoch)
    Cu(H2O)6^2+ (aq) + 2NH3 (aq) -> Cu(H2O)4(OH)2 (s) + 2NH4^+ (aq)

    Can someone please explain to me how I would go about turning this into an ionic equation? Thanks
    Moving your thread to the chemistry forum
    Are you still stuck with this?
 
 
 
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