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    Cu(H2O)6^2+ (aq) + 2NH3 (aq) -> Cu(H2O)4(OH)2 (s) + 2NH4^+ (aq)

    How would I go about turning this into an ionic equation?

    Thanks
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    (Original post by Jessinoch)
    Cu(H2O)6^2+ (aq) + 2NH3 (aq) -> Cu(H2O)4(OH)2 (s) + 2NH4^+ (aq)

    How would I go about turning this into an ionic equation?

    Thanks
    It already is an ionic equation ...
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    (Original post by Jessinoch)
    Cu(H2O)6^2+ (aq) + 2NH3 (aq) -> Cu(H2O)4(OH)2 (s) + 2NH4^+ (aq)

    How would I go about turning this into an ionic equation?

    Thanks
    Looks like you already have it
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    (Original post by charco)
    It already is an ionic equation ...
    Sorry I realised after I posted haha thanks anyway!
 
 
 
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