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Given that X ~ N (15,4), find w when P(│X – 15│ < w) = 0.9 correct to 2 d.p. watch

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    Here's my working out:

    https://imgur.com/a/8yZA5

    The answer is 3.29, what did I do wrong?
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    (Original post by Mathman69)
    Here's my working out:

    https://imgur.com/a/8yZA5

    The answer is 3.29, what did I do wrong?
    Firstly I'm assuming there's a typo in your first line and it's meant to be -w instead of -2?

    You need to get the probability into the form P(a < X < b) before you can normalise.

    So P(-w<X-15<w) becomes P(-w + 15 < X < w + 15). Does this make sense?

    Try carrying on from here and post all your working if you get stuck or get the wrong answer.
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    (Original post by Notnek)
    Firstly I'm assuming there's a typo in your first line and it's meant to be -w instead of -2?

    You need to get the probability into the form P(a < X < b) before you can normalise.

    So P(-w<X-15<w) becomes P(-w + 15 < X < w + 15). Does this make sense?

    Try carrying on from here and post all your working if you get stuck or get the wrong answer.
    Here's my w/o: https://imgur.com/a/zOIU6

    I'm not sure what to do from there.
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    (Original post by Mathman69)
    Here's my w/o: https://imgur.com/a/zOIU6

    I'm not sure what to do from there.
    P(-w/2 < Z < w/2)

    This region is clearly symmetrical about Z = 0. Try drawing a bell curve and think about the regions to the left and right of the required region. Please post your thoughts if you get stuck.
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    (Original post by Notnek)
    P(-w/2 < Z < w/2)

    This region is clearly symmetrical about Z = 0. Try drawing a bell curve and think about the regions to the left and right of the required region. Please post your thoughts if you get stuck.
    Here's what I done: https://imgur.com/a/lKQ9m

    Still don't know how to find the value of w....
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    (Original post by Mathman69)
    Here's what I done: https://imgur.com/a/lKQ9m

    Still don't know how to find the value of w....
    Since the regions on either side must have equal area due to symmetry, the probability of the region on the left must be (1-0.9) \div 2 = 0.05.

    So P(Z&lt;-w/2) = 0.05. Does this make sense and can you carry on from here?
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    (Original post by Notnek)
    Since the regions on either side must have equal area due to symmetry, the probability of the region on the left must be (1-0.9) \div 2 = 0.05.

    So P(Z&lt;-w/2) = 0.05. Does this make sense and can you carry on from here?
    Yes that makes sense, thanks!
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    (Original post by Mathman69)
    Yes that makes sense, thanks!
    This is a common technique that you'll need to get used to. Always draw a quick sketch and think about symmetry.
 
 
 
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