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    A box contains 3 mango yogurts, 4 vanilla yogurts, and 6 cherry yogurts.
    Three yogurts are selected at random from the box without replacement

    Calculate the probability that at least one of the selected yogurt is cherry??
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    (Original post by Sizzo1128)
    A box contains 3 mango yogurts, 4 vanilla yogurts, and 6 cherry yogurts.
    Three yogurts are selected at random from the box without replacement

    Calculate the probability that at least one of the selected yogurt is cherry??
    You can use the fact that P(at least one cherry) = 1 - P(no cherry)
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    (Original post by Integer123)
    You can use the fact that P(at least one cherry) = 1 - P(no cherry)
    Thanks!! how would I calculate P(not cherry) ? ;((
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    (Original post by Sizzo1128)
    Thanks!! how would I calculate P(not cherry) ? ;((
    The probability that the first isn't a cherry is (3+4)/(3+4+6)=7/13. Then the probability that the second is 6/12 (since we are taking them without replacement). Doing the same for the third allows you to multiply the probabilities together to get P(not cherry). Then subtract this from 1.
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    (Original post by Sizzo1128)
    A box contains 3 mango yogurts, 4 vanilla yogurts, and 6 cherry yogurts.
    Three yogurts are selected at random from the box without replacement

    Calculate the probability that at least one of the selected yogurt is cherry??
    Draw a tree diagram and then remember you times along the branches and add across.
 
 
 
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