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Maths Projectile.

An Object is projected vertically upwards from ground level and it's height, H metres, after t seconds is given by the formula:

H=60t5t2H=60t-5t^2

Show that the object is above a height of 90 metres for about 8.5 seconds
working:

90=60t5t290=60t-5t^2

5t260t+90=05t^2-60t+90=0

t212t+18=0t^2-12t+18=0

Then I used the quadratic formula and got 10.24

where have I gone wrong?
Original post by joyoustele
An Object is projected vertically upwards from ground level and it's height, H metres, after t seconds is given by the formula:

H=60t5t2H=60t-5t^2

Show that the object is above a height of 90 metres for about 8.5 seconds
working:

90=60t5t290=60t-5t^2

5t260t+90=05t^2-60t+90=0

t212t+18=0t^2-12t+18=0

Then I used the quadratic formula and got 10.24

where have I gone wrong?


You should get two (positive) roots whose difference is about 8.5 seconds.
Original post by joyoustele
An Object is projected vertically upwards from ground level and it's height, H metres, after t seconds is given by the formula:

H=60t5t2H=60t-5t^2

Show that the object is above a height of 90 metres for about 8.5 seconds
working:

90=60t5t290=60t-5t^2

5t260t+90=05t^2-60t+90=0

t212t+18=0t^2-12t+18=0

Then I used the quadratic formula and got 10.24

where have I gone wrong?


When you solve a quadratic equations with real roots you should get two solutions ...
Because t2-t1 is =10.24-1.76=8.48

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