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    There are numbered cards,without replacement
    2, 3, 3, 4, 4, 4,
    a) what is the probability of the product of two cards selected is 12.
    b) What is the probability of the sum of the two selected cards is even
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    a) this is the same as asking what is the chance of picking a 3 and a 4 ? it looks like without replacement.
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    (Original post by the bear)
    a) this is the same as asking what is the chance of picking a 3 and a 4 ? it looks like without replacement.
    Sorry, i forgot to mention it was without replacement
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    (Original post by Sizzo1128)
    Sorry, i forgot to mention it was without replacement
    if you are used to working with nCr you can find the number of ways of choosing one 3 from 2 and one 4 from 3.

    then divide this number by the total ways of choosing two items from 6
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    (Original post by the bear)
    if you are used to working with nCr you can find the number of ways of choosing one 3 from 2 and one 4 from 3.

    then divide this number by the total ways of choosing two items from 6
    would the answer be,,,
    12/30 and 14/30 ??
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    (Original post by Sizzo1128)
    would the answer be,,,
    12/30 and 14/30 ??
    i got 13/30 for the second answer. the first is correct.
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    (Original post by Sizzo1128)
    would the answer be,,,
    12/30 and 14/30 ??
    Your answers are correct
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    2/5 and 7/15 you got it
 
 
 
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