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    A random variable X has a binomial distribution with parameters n = 40 and p = 0.3. Use a suitable approximation to calculate P(X=15)

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    Where am I going wrong? I literally cannot see anything wrong with what I’ve done therefore I think I must be doing it wrong altogether. If anyone could help explain it would be appreciated.
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    (Original post by _RobbieL_)
    A random variable X has a binomial distribution with parameters n = 40 and p = 0.3. Use a suitable approximation to calculate P(X=15)

    Name:  67809E16-08F2-432A-BC9C-9D052D9D4D7A.jpg.jpeg
Views: 6
Size:  27.0 KB

    Where am I going wrong? I literally cannot see anything wrong with what I’ve done therefore I think I must be doing it wrong altogether. If anyone could help explain it would be appreciated.
    Your area calculation at the end is wrong. Think about what two areas you are subtracting in your calculation and think about if that would actually give you the shaded region. Please post your thoughts if you're still unusre.

    By the way, you should have been able to see that your answer can't be right - with 40 trials it's unlikely that you will get exactly 15 successes (you may have realised this without checking the answer).
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    (Original post by Notnek)
    Your area calculation at the end is wrong. Think about what two areas you are subtracting in your calculation and think about if that would actually give you the shaded region. Please post your thoughts if you're still unusre.

    By the way, you should have been able to see that your answer can't be right - with 40 trials it's unlikely that you will get exactly 15 successes (you may have realised this without checking the answer).
    I realise now that my region calculation was wrong.

    Shouldn’t it be P(Z<1.208) - P(Z<0.863)?

    I just did this and got an answer of 0.0805, but the actual answer is 0.0808. Where else am I going wrong?
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    (Original post by _RobbieL_)
    I realise now that my region calculation was wrong.

    Shouldn’t it be P(Z<1.208) - P(Z<0.863)?

    I just did this and got an answer of 0.0805, but the actual answer is 0.0808. Where else am I going wrong?
    How are you working this out? Using tables or your calculator or another method? Your answer is pretty close to the given answer so it might not be worth worrying.
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    (Original post by Notnek)
    How are you working this out? Using tables or your calculator or another method? Your answer is pretty close to the given answer so it might not be worth worrying.
    Using the standardised normal distribution tables.
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    (Original post by _RobbieL_)
    Using the standardised normal distribution tables.
    Can you please post a link to the tables you are using and tell us the exam board you are doing?
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    (Original post by Notnek)
    Can you please post a link to the tables you are using and tell us the exam board you are doing?
    OCR S2, I’m away from my desk now but you should be able to easily look up the OCR formula book online if you want to, or wait until I encourage myself enough to go back to working lol
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    (Original post by _RobbieL_)
    OCR S2, I’m away from my desk now but you should be able to easily look up the OCR formula book online if you want to, or wait until I encourage myself enough to go back to working lol
    I get the same answer as you using your tables. Was this a textbook answer or mark scheme answer for an exam question?

    I've forgotten how much of a pain it is to use these tables
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    (Original post by Notnek)
    I get the same answer as you using your tables. Was this a textbook answer or mark scheme answer?

    I've forgotten how much of a pain it is to use these tables
    This was a textbook answer so there’s a chance it could be wrong. I’ve got all the questions in this section wrong though so I feel as though I am missing something in my method
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