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    • Thread Starter

    an alpha particle with velocity 3.5x10^6 m/s strikes a block of gold with atomic number 79 and mass number 197, find distance of closest approach between the alpha particle and the gold nucleus, assume only coulombs law holds over such distance, assume mass of proton= mass of neutron= 1.67x10^-27kg. I got the answer 8.9x10^-13 m which is wrong as it says to consider momentum consersation as well as energy conservation.
    Don't know where I'm going wrong.
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     Official Rep
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