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    \dfrac{x}{|x|-3}

    i thought it'd just be discontinuous at 3 since 3-3 s 0 for the bottom of the fraction but -3 also makes this discontinuous why so?

    if i compute -3=x then i get -3/-3-3 which turns out to be 3/6 which is 1/2
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    (Original post by will'o'wisp2)
    \dfrac{x}{|x|-3}

    i thought it'd just be discontinuous at 3 since 3-3 s 0 for the bottom of the fraction but -3 also makes this discontinuous why so?

    if i compute -3=x then i get -3/-3-3 which turns out to be 3/6 which is 1/2
    |-3|=3 so the denom is 0 also...
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    (Original post by RDKGames)
    |-3|=3 so the denom is 0 also...
    now now i thought i had some shred of intelligence left


    thanks for the help
 
 
 
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