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# Chemistry Tritation AS level watch

1. no
2. Post deleted
3. (Original post by Habeeb H Patel)
When silicon tetrachloride is added to water, the following reaction occurs:
SiCl4+2H2O=SiO2+4HCL
1.2g of impure silicon tetrachloride was dissolved in excess water and the resulting solution was made up to 250cm^3. A 25^3 portion was the titrated against 0.10 moldm-3 sodium hydroxide and 18.7cm^3 of the alkali were required. What was the percentage purity of the silicon tetrachloride.

I know how to work it out, but dont understand why NaOH has the same number of moles as HCl....... or is that just an assumption because you dont know the ratio between them
Write out the balanced equation for the reaction between NaOH and HCl.

U should notice something that will answer ur question.

Any other questions let me know.
4. (Original post by Shaanv)
Write out the balanced equation for the reaction between NaOH and HCl.

U should notice something that will answer ur question.

Any other questions let me know.

But why do you have to write out the equation for HCl and NaOH, when the question is about SiCl4.

Also can you help me with this question aswell. An ionic compound has the empircal formula H4N2O3. Suggest the formulae of the ions present. I know N is nitrate but why is H ammonium
5. (Original post by Habeeb H Patel)
But why do you have to write out the equation for HCl and NaOH, when the question is about SiCl4.
U are titrating with NaOH, and u know that NaOH reacts with HCl, HCl is one of the products of ur reaction so it will react with the NaOH.
6. (Original post by Habeeb H Patel)
Also can you help me with this question aswell. An ionic compound has the empircal formula H4N2O3. Suggest the formulae of the ions present. I know N is nitrate but why is H ammonium
Nitrate ion is NO3, so the leftover atoms are N and H4. NH4 is the ammonium ion.

I have left out charges so u dont get confused but dont neglect them.
7. (Original post by Shaanv)
U are titrating with NaOH, and u know that NaOH reacts with HCl, HCl is one of the products of ur reaction so it will react with the NaOH.
Thank you again, the HCL in the original equation is 4HCL, so you find the moles between the NaOH and HCl, then you divide the no. of moles in HCl by 4, to get to SiCl4

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