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    Find the volume bounded by the paraboloid x^2 + y^2 = 4z, the cylinder x^2 + y^2 = 8y and the plane y = 0. (Answer 96pi).

    I don't understand how to get the limit for theta, it is pi,0 but I just can't understand why.

    How does the plane y=0 result in the value of theta being between 0,pi in the x-y plane?

    Thanks
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    (Original post by CHEN20041)
    Find the volume bounded by the paraboloid x^2 + y^2 = 4z, the cylinder x^2 + y^2 = 8y and the plane y = 0. (Answer 96pi).

    I don't understand how to get the limit for theta, it is pi,0 but I just can't understand why.

    How does the plane y=0 result in the value of theta being between 0,pi in the x-y plane?

    Thanks
    \theta measures out a disk parallel xy plane. The plane y=0 cuts this disk in half. Thus \theta's domain halves.
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    (Original post by RDKGames)
    \theta measures out a disk parallel xy plane. The plane y=0 cuts this disk in half. Thus \theta's domain halves.
    Will the same apply if instead of the plane y=0 it was the plane x=0? I'm thinking yeah?
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    (Original post by CHEN20041)
    Will the same apply if instead of the plane y=0 it was the plane x=0? I'm thinking yeah?
    Yes.
 
 
 
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