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    A particle travels in a straight line with speed v. The particle slows down and changes direction. The new speed of the particle is v/2. The new velocity has a component of v/4 in the same direction as the initial path of the particle. Through which angle has the particle turned?

    A 27° B 30° C 45° D 60°

    Can someone show me the working & explanation for this question? The marking scheme says the answer is D.
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    (Original post by Tetisya)
    A particle travels in a straight line with speed v. The particle slows down and changes direction. The new speed of the particle is 2 v . The new velocity has a component of 4 v in the same direction as the initial path of the particle. Through which angle has the particle turned?

    A 27° B 30° C 45° D 60°

    Can someone show me the working & explanation for this question? The marking scheme says the answer is D.
    Have u tried drawing a triangle for the final velocity with a 4v component in the initial direction of motion.

    Once u have got a good diagram the problem becomes trivial.
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    (Original post by Shaanv)
    Have u tried drawing a triangle for the final velocity with a 4v component in the initial direction of motion.

    Once u have got a good diagram the problem becomes trivial.
    Alright, i managed to get the answer. Thanks for the help.
 
 
 
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