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    this is a non calc btw. i'm honestly unsure as to how i approach this question. i know the general equation of a circle is x2 + y2 = r2; does that mean i need to square ten?
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    (Original post by entertainmyfaith)
    this is a non calc btw. i'm honestly unsure as to how i approach this question. i know the general equation of a circle is x2 + y2 = r2; does that mean i need to square ten?
    No, r^2=10
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    (Original post by entertainmyfaith)
    this is a non calc btw. i'm honestly unsure as to how i approach this question. i know the general equation of a circle is x2 + y2 = r2; does that mean i need to square ten?
    You just need to work out the gradient OP, then use the negative reciprocal of it to construct the line PQ. Then just find where it intersects the x-axis.
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    (Original post by RDKGames)
    You just need to work out the gradient OP, then use the negative reciprocal of it to construct the line PQ. Then just find where it intersects the x-axis.
    how would i work out the gradient if i only know that the x-coordinate of p is 1?
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    (Original post by entertainmyfaith)
    how would i work out the gradient if i only know that the x-coordinate of p is 1?
    You can work out the y-coordinate of P using the equation.
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    (Original post by RDKGames)
    You can work out the y-coordinate of P using the equation.
    oh, that makes sense. thank you!
 
 
 
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