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    For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

    Help please
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    wtf
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    (Original post by lolu123)
    wtf
    ikr
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    (Original post by Student111123)
    ikr
    is it alevels
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    (Original post by Student111123)
    For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

    Help please
    I'm assuming this is a titration calculation question.

    First calculate how many moles of Ba(OH)2 you have.
    Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation.
    From that, you can find the number of moles of HNO3 you need.
    Then since you know the concentration of HNO3 you can find the volume.
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    (Original post by TheMindGarage)
    I'm assuming this is a titration calculation question.

    First calculate how many moles of Ba(OH)2 you have.
    Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation.
    From that, you can find the number of moles of HNO3 you need.
    Then since you know the concentration of HNO3 you can find the volume.
    How you do dat
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    (Original post by Student111123)
    For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

    Help please
    moles of Ba(OH)2= concentration x volume = 0.75
    the molar ratio of Ba(OH)2: HNO3 is 1:2 from the equation, so there is equal moles
    therefore the volume of HNO3 is moles/concentration so (0.75x2)/4=0.375dm3
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    (Original post by Carolyne2891)
    moles of Ba(OH)2= concentration x volume = 0.75
    the molar ratio of Ba(OH)2NO3 is 1:1 from the equation, so there is equal moles
    therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...
    But the options given to me were:
    a) 0.75 dm3
    b) 0.075 dm3
    c) 0.375 dm3
    d) 0.0375 dm3
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    (Original post by Student111123)
    But the options given to me were:
    a) 0.75 dm3
    b) 0.075 dm3
    c) 0.375 dm3
    d) 0.0375 dm3
    think it's c from doing (0.75x2)/4?? hahah idk it just works
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    (Original post by Carolyne2891)
    moles of Ba(OH)2= concentration x volume = 0.75
    the molar ratio of Ba(OH)2NO3 is 1:1 from the equation, so there is equal moles
    therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...
    (Original post by Student111123)
    For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

    Help please
    Ratio isn't 1:1, it's 1:2 as shown in OP's original balanced equation.
    You need twice as many moles of HNO3 as you have Ba(OH)2.
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    (Original post by PengDog:))
    a^2+b^2=c^2

    I think this might help.
    Are you sure you posted on the right thread??
 
 
 
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