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    Struggling to find a solution. Used the nth term formula but can't figure out where to go from there.

    Julie earns £y in her first year of work.
    Her salary is increased by £650 every year how much will she earn in the 5th year & the nth year.
    i) Find the 5th term
    ii) Find the nth term
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    (Original post by the1stepicface)
    Struggling to find a solution. Used the nth term formula but can't figure out where to go from there.

    Julie earns £y in her first year of work.
    Her salary is increased by £650 every year how much will she earn in the 5th year & the nth year.
    i) Find the 5th term
    ii) Find the nth term
    so if you think about it how did you calculate the 5th year?

    well what you did was y \times 4\times 650 right?

    so if you think about it this is equivalent to y x (5-1)x650 right? similar for the 4th term which would be y x (4-1)x650 ok?

    so if you keep going and keep the pattern going what you can do is let's say 100

    you know the 100th term will be y x (100-1)x650 right? so if we keep going higher and higher we can go to the nth term right? can you complete the pattern which will answer the question?
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    so if you think about it how did you calculate the 5th year?

    well what you did was right?

    so if you think about it this is equivalent to y x (5-1)x650 right? similar for the 4th term which would be y x (4-1)x650 ok?

    so if you keep going and keep the pattern going what you can do is let's say 100

    you know the 100th term will be y x (100-1)x650 right? so if we keep going higher and higher we can go to the nth term right? can you complete the pattern which will answer the question?
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    (Original post by Leafy is beafy)
    so if you think about it how did you calculate the 5th year?

    well what you did was right?

    so if you think about it this is equivalent to y x (5-1)x650 right? similar for the 4th term which would be y x (4-1)x650 ok?

    so if you keep going and keep the pattern going what you can do is let's say 100

    you know the 100th term will be y x (100-1)x650 right? so if we keep going higher and higher we can go to the nth term right? can you complete the pattern which will answer the question?
    thanks for copying bro :P
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    (Original post by the1stepicface)
    Struggling to find a solution. Used the nth term formula but can't figure out where to go from there.

    Julie earns £y in her first year of work.
    Her salary is increased by £650 every year how much will she earn in the 5th year & the nth year.
    i) Find the 5th term
    ii) Find the nth term
    we know it increases by 640 each year, hence the nth term should be  650n where n is the year

    So to work out the 5th year, you would sub in  n = 5

    Therefore to find out the 5th year do 650 x 5.

    For the second part, it's simply the nth term, or the rule.

    Hope that helps
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    (Original post by the1stepicface)
    Struggling to find a solution. Used the nth term formula but can't figure out where to go from there.

    Julie earns £y in her first year of work.
    Her salary is increased by £650 every year how much will she earn in the 5th year & the nth year.
    i) Find the 5th term
    ii) Find the nth term
    Looks like the nth term formula has to be a linear function: if the sum of money increases by 650 pound every year, so this means that the increase is a constant which goes for the named function.

    So, it is y(n) = a(n) (n-1)d in general.

    Also increasing by 650 in every year means that the difference (depicted as a 'd' in the formula) is always 650 to the year before, and the year before is n-1 as a mathematical term. a(n) (not given in the text) is the sum of money in the certain year, while 'n' is the number of the year.

    Can you solve it this time?
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    Thank you, I've worked it out now.
 
 
 
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