Does anyone know how to solve this with full working?
________ + _______
X + 1 2x-1
Turn on thread page Beta
Quadratic equation watch
- Thread Starter
- 13-11-2017 19:06
- 13-11-2017 19:32
I don't think your format is very good - what is the question exactly? Can you write it out in words?
- 13-11-2017 19:36
What is the question exactly? It is not clear.
- 13-11-2017 19:41
If the question is:
(3 / x+1) + (4/2x-1)
1) Make the denominators of both fractions equal as this is the only way we will be able to add them. We can do this by multiplying one fraction by the denominator of the other leaving us with:
[ 3(2x - 1) / (x+1)(2x-1)] + [ 4(x + 1) / (x+1)(2x-1)]
2) As they both fractions now have the same denominator we can add the numerators as well as expand the brackets:
[ (6x -3 + 4x + 4) ] / [ (x+1)(2x-1) ]
3) We can now collect light terms:
[ (10x + 1) ] / [ (x+1)(2x-1) ]
- This should be our final answer