Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    7
    ReputationRep:
    The frictional force on a vehicle travelling on a road is 0.6 x the vehicles weight. G = 9.81 ms-2. For a vehicle of mass 1200kg.
    Show that the deceleration is 5.9ms-1
    Posted on the TSR App. Download from Apple or Google Play
    Offline

    1
    ReputationRep:
    Weight = mass x gravity
    = 1200kg x 9.81
    =11,772 N

    Frictional force = 0.6 x weight
    =0.6 x 11772
    =7063.2 N

    Force = mass x acceleration
    7063.2 = 1200 × acceleration
    acceleration = 5.886
    =5.9ms^-2
    Posted on the TSR App. Download from Apple or Google Play
 
 
 
Poll
Do you agree with the PM's proposal to cut tuition fees for some courses?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.