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    Accidents occur at a factory at an average rate of 5 per month. Find the probabilities that,
    (b) there will be exactly 62 in a year.

    so far I have figured out the new mean as 60 and have tried to work out
    p(x=62) = (e^-60 x 60^62)/62!
    I have typed this into the calculator and got error. Thanks in advance
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    (Original post by Butterflyshy)
    Accidents occur at a factory at an average rate of 5 per month. Find the probabilities that,
    (b) there will be exactly 62 in a year.

    so far I have figured out the new mean as 60 and have tried to work out
    p(x=62) = (e^-60 x 60^62)/62!
    I have typed this into the calculator and got error. Thanks in advance
    the value of lambda is scaled linearly for different time periods. in 12 months there will be on average 12 times as many accidents as in 1 month.

    your method is right... the value is

    0.04895671125 from the computer.

    on your calculator it is better to do an approximation.... Normal with mean lambda & Variance lambda should work.
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    you will need to apply a continuity correction as Poisson is for discrete data & Normal is for continuous.
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    (Original post by the bear)
    you will need to apply a continuity correction as Poisson is for discrete data & Normal is for continuous.
    thanks I'm getting the right answer now
 
 
 
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