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Forces and Equilibrium Question, Help Needed. watch

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    A particle of mass m kg is placed on a smooth plane inclined at an angle b to the horizontal. Find the magnitude of the force required to keep the particle in equilibrium if it acts at an angle of a to the slope. What is the least possible force needed to keep the particle in equilibrium?

    I have resolved forces and got: (R is normal reaction force, F is the force required to keep the particle in equilibrium and 10m is the weight)
    In the vertical direction: R + Fsin(a) = 10mcos(b)
    In the horizontal direction: Fcos(a) = 10msin(b)

    Anyone have any ideas?
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.
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    You have done it wrong, for the particle weighing 10m newton's to be in equilibrium you need the the reaction forces equations the particle weight component, so R= 10mcos(b) and 10msin(b)=F, it quite a simple question, you are overcomplicated it by over splitting the weight component, you'll get better with practice.
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    (Original post by MadMaths)
    You have done it wrong, for the particle weighing 10m newton's to be in equilibrium you need the the reaction forces equations the particle weight component, so R= 10mcos(b) and 10msin(b)=F, it quite a simple question, you are overcomplicated it by over splitting the weight component, you'll get better with practice.
    Thanks for the reply, but I don't think you are correct. I think you are trying to remove the complications, but thanks! This is very arrogant of you!!!!

    A particle of mass m kg is placed on a smooth plane inclined at an angle b to the horizontal. Find the magnitude of the force required to keep the particle in equilibrium if it acts at an angle of a to the slope. What is the least possible force needed to keep the particle in equilibrium?
 
 
 

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