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Binomial Expansion Question?!?!

I'm struggling with this question?:

Given that (1 + kn)^n = 1 + 24x + 240x^2 + ...
Work out the values of k and n


Any help would be appreciated

Thanks
Original post by pkt01
I'm struggling with this question?:

Given that (1 + kn)^n = 1 + 24x + 240x^2 + ...
Work out the values of k and n


Any help would be appreciated

Thanks

I'm assuming you mean (1+kx)n(1+kx)^n
Firstly think about how you would expand it if they were numbers
eg. (1+7x)3=13+3!1!2!×12×7x etc.(1+7x)^3 = 1^3 + \frac{3!}{1!2!}\times{1^2}\times{7x} \text{ etc.}
Then replicate this with k and n instead.
You should come to some equations in terms of k and n which you can then solve :smile:
(edited 6 years ago)
Original post by pkt01
I'm struggling with this question?:

Given that (1 + kn)^n = 1 + 24x + 240x^2 + ...
Work out the values of k and n


Any help would be appreciated

Thanks


Use the same method you'd normally use but use k and n in place of the numbers. Then you should find expressions for the x coefficient and for the x^2 coefficient and set them equal to 24 and 240.
OK thanks :smile:
Original post by pkt01
OK thanks :smile:

No worries :smile:

Posted from TSR Mobile
Original post by quirkyqwerty
I'm struggling with this question?:

Given that (1 + kn)^n = 1 + 24x + 240x^2 + ...
Work out the values of k and n


Any help would be appreciated

Thanks

which paper year is this

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