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# Limits watch

1. limit x->2^- (x^2-x-2)/mod(x-2)? I got the answer to the RHS of 2 correct but not the LHS of 2 how do i get -3?
2. (Original post by Salimshady007)
limit x->2^- (x^2-x-2)/mod(x-2)? I got the answer to the RHS of 2 correct but not the LHS of 2 how do i get -3?
Do you mean ? What's the RHS and LHS...?

Simply note that .

It might be easier if you try and work out the limit of as first. The idea is more or less the same.
3. (Original post by Zacken)
Do you mean ? What's the RHS and LHS...?

Simply note that .

It might be easier if you try and work out the limit of as first. The idea is more or less the same.
No, I got the right answer for RHS which is 3 but the LHS is -3 when I got 0
4. (Original post by Salimshady007)
No, I got the right answer for RHS which is 3 but the LHS is -3 when I got 0
Well yes, that’s why i told you to work out what the limit of x/|x| is as x goes to 0 from either side. What is it?
5. (Original post by Salimshady007)
No, I got the right answer for RHS which is 3 but the LHS is -3 when I got 0
(Original post by Zacken)
Well yes, that’s why i told you to work out what the limit of x/|x| is as x goes to 0 from either side. What is it?
Getting 0 seems to indicate sufficient confusion that I think it would be a good idea if Salimshady007 posts/explains how he got that result.
6. I knew that the approaching 2 from the LHS made me chose -x so I had Limx->2^- (x-2)(x+1)/-x-2 which gives me 0 as I plugged in 2 but its supposed to be -3.
7. When x < 2, |x-2| = 2-x, not -x-2.
8. So that's where I was wrong, thank you.

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