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#1
Can any one help me plz to solve y= ab^x if two points are ( 2,8) (0.5, 1)
0
2 years ago
#2
(Original post by sykhan)
Can any one help me plz to solve y= ab^x if two points are ( 2,8) (0.5, 1)
Well from those two points you are able to get two equations in and by simply substituting the coordinates into it. Try that.
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2 years ago
#3
so let y = 8 and x = 2

then repeat for the other coordinates.
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2 years ago
#4
Taking logs might make things easier...
0
2 years ago
#5
I'd form the two equations, and divide one by the other - doesn't even need a calculator.
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#6
When i divide both equation i got b^1.5= 8 now i dont know how to get rid of this decimal power. Plz help me
0
2 years ago
#7
(Original post by sykhan)
When i divide both equation i got b^1.5= 8 now i dont know how to get rid of this decimal power. Plz help me
Square the whole thing.
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#8
(Original post by DFranklin)
Taking logs might make things easier...
plz show me how?? Plz
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#9
Can u solve the question for me plz as its gv me decimal power. And i dont know how to get rid of decimal power to get b.
0
2 years ago
#10
(Original post by sykhan)
When i divide both equation i got b^1.5= 8 now i dont know how to get rid of this decimal power. Plz help me
at GCSE level, you can estimate roots; so you can take the square root of 8 as 2, and because root 2.5 is close to 2 and would give a greater answer, add on around 0.7/0.8 so you get 2.8.

At A-level it's completely different of couce
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2 years ago
#11
Form and solve the system of equations.
0
2 years ago
#12
(Original post by sykhan)
When i divide both equation i got b^1.5= 8 now i dont know how to get rid of this decimal power. Plz help me
If you square the whole equation you get:

And using the rules for indices we have:

And you've eliminated the decimal part of the power.

Can you finish from there?
0
#13
Yes now i did it many thanks😊 so kind of u.
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