The curve C has equation y=4x^2 + (5x-1)/x
a. Find f'(x)
For this I've got 8x + x^-2
b. Find the x-coordinate of the stationary point of C
Now this is where it all goes downhill because I got x=0 but looking on Desmos says that x=0 is a vertical asymtote.
c. Determine whether this stationary point is a maximum or a minimum
To do this I know you have to feed the x-coordinate back through the f''(x) function, and if it's negative it's a maximum and if it's positive it's a minimum.