need help in solving a problem in accelerated motion

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=spencer=
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The metal plate is released from rest and falls a distance of 0.200m before breaking light beam 1. It then falls a further 0.250m before breaking light beam 2.
a) Calculate the time taken for the plate to fall 0.200m from rest (you may assume that the metal plate falls with an acceleration of free fall.)
b) The timer measures the speed of the metal plate as it falls through each light beam. The speed as it falls through light beam 1 is 1.92ms and the speed as it falls through light beam 2 is 2.91ms.
(i) Calculate the acceleration of the plate between two light beams.
(ii) State and explain one reason why the acceleration of the plate is not equal to the acceleration of free fall.
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RDKGames
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(Original post by =spencer=)
The metal plate is released from rest and falls a distance of 0.200m before breaking light beam 1. It then falls a further 0.250m before breaking light beam 2.
a) Calculate the time taken for the plate to fall 0.200m from rest (you may assume that the metal plate falls with an acceleration of free fall.)
b) The timer measures the speed of the metal plate as it falls through each light beam. The speed as it falls through light beam 1 is 1.92ms and the speed as it falls through light beam 2 is 2.91ms.
(i) Calculate the acceleration of the plate between two light beams.
(ii) State and explain one reason why the acceleration of the plate is not equal to the acceleration of free fall.
What have you tried?
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=spencer=
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(Original post by RDKGames)
What have you tried?
i tried using the equation s=ut+1/2at^2 for the first one and the answer im getting is t=0.202. is it correct?
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RDKGames
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(Original post by =spencer=)
i tried using the equation s=ut+1/2at^2 for the first one and the answer im getting is t=0.202. is it correct?
I agree with that.
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=spencer=
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(Original post by RDKGames)
I agree with that.
thank you,
a little more help with the part b of the question.
so for b (i) i got (2.91-1.92)/0.226=4.38
is it correct?
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