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Chemistry alevel help please

butan-1-ol was reacted with an excess of propanoic acid in the presence of a small amount of concentrated sulfuric acid. 6.0g of the alcohol was produced 7.4g of the ester. What is the percentage yield of the ester?
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harry44!
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Original post by computerwizz
butan-1-ol was reacted with an excess of propanoic acid in the presence of a small amount of concentrated sulfuric acid. 6.0g of the alcohol was produced 7.4g of the ester. What is the percentage yield of the ester?


1-Find number of moles of reactant

The acid is in excess so the alcohol is the limiting factor here...
Mr butan-1-ol: 72
n = m/ mrn = 6.0 / 72 = 0.08333 mol

2-Find theoretical mass of ester produced
The alcohol and acid react in a 1 to 1 ratio
So theoretically 0.083333 mol of ester produced
Mr of ester = 130

Now find the massm = n X mrm = 0.08333 X 130 = 10.83g

3-Find the % yield(Actual Mass / Theoretical Mass) X 100
(7.4 / 10.8) X 100 = 69%
Original post by harry44!
1-Find number of moles of reactant

The acid is in excess so the alcohol is the limiting factor here...
Mr butan-1-ol: 72
n = m/ mrn = 6.0 / 72 = 0.08333 mol

2-Find theoretical mass of ester produced
The alcohol and acid react in a 1 to 1 ratio
So theoretically 0.083333 mol of ester produced
Mr of ester = 130

Now find the massm = n X mrm = 0.08333 X 130 = 10.83g

3-Find the % yield(Actual Mass / Theoretical Mass) X 100
(7.4 / 10.8) X 100 = 69%


Thanks! :smile:

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