K equivalent in springs arranged in parallel combination
I do know the formula for k equivalent in springs is
k1 + k2
But for this following question I don't think just writing the equation would be enough for 2 marks.
Q) If two springs, each of stiffness k, are connected side-by-side in parallel, the stiffness of the combination is 2k. Explain why.
So how do I explain?
Thank you all for your fantastic help and support!
k1 + k2
But for this following question I don't think just writing the equation would be enough for 2 marks.
Q) If two springs, each of stiffness k, are connected side-by-side in parallel, the stiffness of the combination is 2k. Explain why.
So how do I explain?
Thank you all for your fantastic help and support!
F=ke, when you apply force F on 2 spring, extension is only e/2 so stiffness is 2k.
Original post by Arctic Kitten
F=ke, when you apply force F on 2 spring, extension is only e/2 so stiffness is 2k.
Thanks a lot Arctic Kitten! (:
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